Knowledge Keeps You One Step Ahead

Friday, August 15, 2025

NIOS Class 10 Atoms and Molecules Worksheet 3 Solutions

In this post you will find answers of questions of Worksheet -3 NIOS class 10 science (Code-212) Chapter 3- Atoms and Molecules with complete explanation.

NIOS Class 10 Science (212) Worksheet 3 Solutions


Atoms and Molecule Worksheet 3 Answers


Q1. Pure water contains 11.11% of hydrogen and 88.89% of oxygen by mass. What will be the composition of compounds such as ammonia, carbon dioxide, sodium chloride and hydrogen sulphide.

Answer

 


Percentage of elements by mass in Ammonia


Mass of nitrogen (N)=14

Mass of hydrogen (H)= 1 ×3 =3

Total mass 17g/mol





Percentage of elements by mass in CO2


Mass of Carbon (C) = 12

Mass of oxygen (O) = 16 ×2 =32

Total mass = 44g/mol



 


Percentage of elements by mass in NaCl


Mass of sodium (Na) = 23

Mass of chlorine (Cl) =35.5

Total mass =58.5g/mol



 

 


Percentage of elements by mass in H2S


Mass of hydrogen (H)= 1×2 =2

Mass of sulphur (S) = 32

Total mass = 34g/mol

 

 




 

Q2. Analyse if everything is made of atoms. How could scientists be sure that there was not anything smaller than an atom? Explain by using your knowledge of chemistry.

Answer

Everything  is made up of atoms


 Yes, all matter (solid, liquid and gas) is made up of tiny particles called atoms. According to Dalton’s atomic theory- Atom is the smallest particle and is basic building block of matter.


Scientists thought atoms were indivisible


The word ‘Atom’ comes from Greek word ‘ Atomos’ which means indivisible.

John Dalton proposed atomic theory:

   1.  Atoms are the smallest indivisible particles.

   2.  They cannot be created or destroyed in chemical reaction.


Discovery of smaller particles than atoms


J.J. Thomson discovered electrons and Rutherford discovered positively charged particles in the nucleus of atom. James Chadwik discovered neutrons in the nucleus.

 


Q3. Atoms were thought to be indivisible, later as per studies, we know that they are made of smaller particles, can we still consider them as building blocks of matter. Give reasons in support of your answer.

Answer

Yes, atoms are still considered the basic building blocks of matter. We know atoms are divisible and made-up smaller particles – electrons, protons and neutrons.


Reasons

   1. Atoms are divisible into subatomic particles but these particles cannot take part in chemical reaction and does not show chemical properties.


   2. Atoms combine in fixed ratio to form molecules but subatomic particles cannot do.


   3. Structure of substance (solid, liquid and gas) depends upon arrangement of atoms.


So, atoms are divisible into smaller subatomic particles but they are fundamental units of matter.

 

 

Q4. Nitrogen and hydrogen combine in the ratio 14:3 by mass of form ammonia molecule. Find the formulae of ammonia molecule by calculating the molar ratio?

Answer

Mass ratio of Nitrogen: Hydrogen =14:3

Atomic mass of Nitrogen = 14u

Atomic mass of Hydrogen = 1u


Moles of each element


 



Molar ratio

Nitrogen : Hydrogen = 1:3


Chemical formula of ammonia

1 atom of nitrogen and 3 atoms of hydrogen combines to form 1 molecule of ammonia

NH3



Q5. C6H12O6 is the formula for Glucose. What information do you get from this formula?

Answer

We can get following information through the chemical formula(here C6H12O6):


(i)      Elements present: Glucose is made up of carbon(C), Hydrogen(H) and oxygen(O) atoms.


(ii)    Number of atoms of each element: In glucose , carbon has 6 atoms, hydrogen has 12 atoms and oxygen has  6 atoms.


(iii)    Molecular composition: Atoms are combined in fixed ration 6:12:6 or 1:2:1


(iv)    Molar mass of glucose:


Carbon = 12 × 6=72 g


Hydrogen = 1 ×12=12 g


Oxygen = 16 × 6 =96 g


Total mass = 72 + 12+ 96 =180g/mol


(v)  Nature of compound: Glucose is an organic compound and it is a primary source of energy in living beings.


So, a formula provide the above information about a  substance.

 

Q6. As we know our body constituted approximately 80% of water. Calculate the number of water molecules which are present in the body of a young person whose weight is 62 kg.

Answer

Mass of water in the body

 Mass of water = 80% of total mass of the body

  


Convert kg to grams

49.6 kg= 49600g


Find moles of water

 Molar mass of water = 18g/mol




Calculate number of molecules


Avogadro’s number (NA) = 6.022 × 1023 molecules/mol


Number of molecules = moles× NA


               = 2755.56× 6.022 × 1023


               = 1.66 ×1027 molecules


So, 1.66 ×1027 water molecules which are present in the body of a young person whose weight is 62 kg.



Q7. Calculate the molecular mass of the following compounds: MgO. CaO, NH3, H2SO4.

Answer

    1. Molecular mass of Magnesium oxide (MgO)

    Mg= 24.3u

     O = 16u

  Molecular mass = 24.3+ 16 = 40.3 u


    2. Molecular mass of Calcium oxide (CaO)

    Ca=  40.1 u

 O= 16 u

 Molecular mass = 40.1+ 16 = 56.1 u


    3. Molecular mass of Ammonia (NH3)

     N= 14 u

     H = 1× 3 =3u

Molecular mass = 14 + 3 = 17u


    4. Molecular mass of Sulphuric Acid (H2SO4)

    H= 1 ×2 = 2u

    S= 32.1u

   O = 16 ×4 =64

Molecular mass = 2 + 32.1 + 64 = 98.1u


Compound

 Molecular mass

MgO

40.3 u

CaO

56.1 u

NH3

17u

H2SO4

98.1 u

 

 

Q8. These are different forms of oxygen ie 2O, O2 and O3. What is the difference between 2O, O2 and O3.

Answer

 

Features

2 O

O2

O3

Composition

2 separate atoms

Two atoms bonded

Three atoms bonded

Stability

Extremely low

High

Moderate

Reactivity

 High

Moderate

Very high

Occurrence

Upper atmosphere

Everywhere

Ozone layer

Role

 Initial radical chemistry

Respiration, combustion

UV absorption

 

 

Q9. Atomic number of uranium is 92. If uranium has three isotopes having 141, 143 and 145 neutrons in their nucleus. How would they be the symbol of the isotopes? How does isotopes different form isobars?

Answer

Find mass number of isotopes


Mass number (A)= Number of protons(Z) + Number of neutrons(N)


Since uranium’s atomic number id 92


Isotope 1: mass number = 92 +141=233

Isotope 2: mass number = 92+143 =235

Isotope 3: mass number = 92 +145 =237


Symbols of isotopes

  ,  ,


Difference between isotopes and isobars

Isotopes

Isobars

Atoms of same elements having similar atomic number but different mass numbers

Atoms of different elements having same mass number but different atomic numbers.

 ,  ,

 ,  

 

 

Q10. “A sample of a pure substance always consists of the same elements combined in the same proportion by mass”. Which law has proposed this? Explain the law in details.

Answer

This is the Law of constant Proportion (law of definite proportion)

This law was proposed by Joseph Proust. According to this law ‘ If a compound is pure, the mass ratio of its constituent elements remains constant.’


Example – H2O

 Mass of hydrogen =1×2=2g

Mass of oxygen = 16g

Ration by mass = 2 : 16  or 1:8


This ration is always 1:8, whether water is from rain, river or sea.


No comments:

Post a Comment