NIOS Class 10 Atoms and Molecules Worksheet 3 Solutions

In this post you will find answers of questions of Worksheet -3 NIOS class 10
science (Code-212) Chapter 3- Atoms and Molecules with complete explanation.

NIOS Class 10 Science (212) Worksheet 3 Solutions

 

Atoms and Molecule Worksheet 3 Answers

 

Q1. Pure water contains 11.11% of hydrogen and 88.89% of oxygen by mass. What will be the composition of compounds such as ammonia, carbon dioxide, sodium chloride and hydrogen sulphide.

Answer

 

Percentage of elements by mass in Ammonia

 

Mass of nitrogen (N)=14

Mass of hydrogen (H)= 1 ×3 =3

Total mass 17g/mol

 

Percentage of elements by mass in CO2

Mass of Carbon (C) = 12

Mass of oxygen (O) = 16 ×2 =32

Total mass = 44g/mol

 

 

 

Percentage of elements by mass in NaCl

 

Mass of sodium (Na) = 23

Mass of chlorine (Cl) =35.5

Total mass =58.5g/mol

 

 

 

 

Percentage of elements by mass in H2S

 

Mass of hydrogen (H)= 1×2 =2

Mass of sulphur (S) = 32

Total mass = 34g/mol

 

 

 

 

 

 

Q2. Analyse if everything is made of atoms. How could scientists be sure that there was not anything smaller than an atom? Explain by using your knowledge of chemistry.

Answer

Everything  is made up of atoms

 Yes, all matter (solid, liquid and gas) is made up of tiny particles called atoms. According to Dalton’s atomic theory-
Atom is the smallest particle and is basic building block of matter.

Scientists thought atoms were indivisible

The word ‘Atom’ comes from Greek word ‘ Atomos’ which means indivisible.

John Dalton proposed atomic theory:

   1.  Atoms are the smallest indivisible particles.

   2.  They cannot be created or destroyed in chemical reaction.

 

Discovery of smaller particles than atoms

J.J. Thomson discovered electrons and Rutherford discovered positively charged
particles in the nucleus of atom. James Chadwik discovered neutrons in the nucleus.

Q3. Atoms were thought to be indivisible, later as per studies, we know that they are made of smaller particles, can we still consider them as building blocks of matter. Give reasons in support of your answer.

Answer

Yes, atoms are still considered the basic building blocks of matter. We know atoms
are divisible and made-up smaller particles – electrons, protons and neutrons.

Reasons

   1. Atoms are divisible into subatomic particles but these particles cannot take part in
chemical reaction and does not show chemical properties.

   2. Atoms combine in fixed ratio to form molecules but subatomic particles cannot do.

   3. Structure of substance (solid, liquid and gas) depends upon arrangement of atoms.

So,atoms are divisible into smaller subatomic particles but they are fundamental
units of matter.

 

Q4. Nitrogen and hydrogen combine in the ratio 14:3 by mass of form ammonia molecule. Find the formulae of ammonia molecule by calculating the molar ratio?

Answer

Mass ratio of Nitrogen: Hydrogen =14:3

Atomic mass of Nitrogen = 14u

Atomic mass of Hydrogen = 1u

Moles of each element

 

Moles= Mass givenAtomic mass

 

 

 

 

 

 

 

 

Molarratio

Nitrogen : Hydrogen = 1:3

 

Chemical formula of ammonia

1atom of nitrogen and 3 atoms of hydrogen combines to form 1 molecule of ammonia (NH3)

Q5.C6H12O6 is the formula for Glucose. What information do you get from this formula?

Answer

We can get following information through the chemical formula(here C6H12O6):

(i)      Elements present: Glucose is made up of carbon(C), Hydrogen(H) and oxygen(O) atoms.

(ii)    Number of atoms of each element: In glucose , carbon has 6 atoms, hydrogen has 12 atoms and oxygen has  6 atoms.

(iii)    Molecular composition: Atoms are combined in fixed ration 6:12:6 or 1:2:1

(iv)    Molar mass of glucose:

Carbon = 12 × 6=72 g

Hydrogen = 1 ×12=12 g

Oxygen = 16 × 6 =96 g

Total mass = 72 + 12+ 96 =180g/mol

 

(v)  Nature of compound: Glucose is an organic compound and it is a primary source of energy in living beings.

So, a formula provide the above information about a  substance.

 

Q6. As we know our body constituted approximately 80% of water. Calculate the number of water molecules which are present in the body of a young person whose weight is 62 kg.

Answer

Mass of water in the body

 Mass of water = 80% of total mass of the body

 

 

Convert kg to grams

49.6 kg= 49600g

 

Find moles of water

 Molar mass of water = 18g/mol

 

 

 

 

 

Calculate number of molecules

 

Avogadro’s number (NA) = 6.022 × 1023 molecules/mol

 

Number of molecules = moles× NA

 

               = 2755.56× 6.022 × 1023

 

               = 1.66 ×1027 molecules

 

So, 1.66 ×1027 water molecules which are present in the body of a young person whose weight is 62 kg.

 

 

Q7. Calculate the molecular mass of the following compounds: MgO. CaO, NH3, H2SO4.

Answer

    1.Molecular mass of Magnesium oxide (MgO)

    Mg= 24.3u

     O = 16u

  Molecular mass = 24.3+ 16 = 40.3 u

 

    2.Molecular mass of Calcium oxide (CaO)

    Ca=  40.1 u

     O= 16 u

 Molecular mass = 40.1+ 16 = 56.1 u

 

    3. Molecular mass of Ammonia (NH3)

     N= 14 u

     H = 1× 3 =3u

Molecular mass = 14 + 3 = 17u

 

    4. Molecular mass of Sulphuric Acid (H2SO4)

    H= 1 ×2 = 2u

    S= 32.1u

   O = 16 ×4 =64

Molecular mass = 2 + 32.1 + 64 = 98.1u

 

Compound

 Molecular mass

MgO

40.3 u

CaO

56.1 u

NH3

17u

H2SO4

98.1 u

 

 

Q8. These are different forms of oxygen ie 2O, O2 and O3. What is the difference between 2O, O2 and O3.

Answer

Features

2 O

O2

O3

Composition

2 separate atoms

Two atoms bonded

Three atoms bonded

Stability

Extremely
low

High

Moderate

Reactivity

 High

Moderate

Very high

Occurrence

Upper atmosphere

Everywhere

Ozone layer

Role

 Initial radical chemistry

Respiration, combustion

UV absorption

 

 

Q9.Atomic number of uranium is 92. If uranium has three isotopes having 141, 143 and 145 neutrons in their nucleus. How would they be the symbol of the isotopes? How does isotopes different form isobars?

 

Answer

Find mass number of isotopes

Mass number (A)= Number of protons(Z) + Number of neutrons(N)

 

Since uranium’s atomic number id 92

 

Isotope 1: mass number = 92 +141=233

Isotope 2: mass number = 92+143 =235

Isotope 3: mass number = 92 +145 =237

 

Symbols of isotopes

   ,

 

Difference between isotopes and isobars

Isotopes

Isobars

Atoms of same elements having similar atomic number but different mass numbers

Atoms of different elements having same mass number but different atomic numbers.

  ,

 

 

Q10.“A sample of a pure substance always consists of the same elements combined in the same proportion by mass”. Which law has proposed this? Explain the law in details.

Answer

This is the Law of constant Proportion (law of definite proportion)

This law was proposed by Joseph Proust. According to this law ‘ If a compound is
pure, the mass ratio of its constituent elements remains constant.’

 

Example– H2O

 Mass of hydrogen =1×2=2g

Massof oxygen = 16g

Ration by mass = 2 : 16  or 1:8

 

This ration is always 1:8, whether water is from rain, river or sea.